I miss the following operation:
bytes->byte-vector : (list byte) -> byte-vector
Return a newly allocated byte-vector whose elements
are the same as the elements of the list
The function bytes->byte-vector could be defined as
(define (bytes->byte-vector bytes)
(apply byte-vector bytes))
but since apply copies the elements of bytes, this would
be inefficient.
--
Jens Axel Søgaard