266: The expr syntax

by José Bollo

Status

This SRFI is currently in draft status. Here is an explanation of each status that a SRFI can hold. To provide input on this SRFI, please send email to srfi-266@nospamsrfi.schemers.org. To subscribe to the list, follow these instructions. You can access previous messages via the mailing list archive.

Abstract

The syntax expr allows one to write arithmetic expressions using a syntax near to mathematical notation, potentially improving the readability of Scheme programs.

Issues

Rationale

Scheme programmers expressing arithmetic expression see all over their code the gap between what they learnt at school for expressing arithmetic formulae and what is written in Scheme.

Here is an example of Scheme for computing the root of a quadratic.

   (let-values (((q r) (floor/ count size)))
      (if (zero? r) q (+ q 1)))

   (let ((rdelta (sqrt (- (square b) (* 4 a c)))))
      (values (/ (+ (- b) rdelta) (* 2 a))
              (/ (- (- b) rdelta) (* 2 a))))

   ; computes the smallest integer k >= 0 such that (45-5k)% <= dark/total <= (55+5k)%)
   (define k (- (quotient (+ (abs (- (* dark 20) (* total 10))) total -1) total) 1))

This SRFI describes the syntax expr that fills the gap between Scheme and mathematics, at least for arithmetic. Using this syntax, the above examples can be written as below:

   (expr floor/ (count size) as q r in q + ? positive? r)

   (expr sqrt(square b - 4 * a * c) as delta in
           values ((- b + delta) / (2 * a)
	           (- b - delta) / (2 * a)))

   (define k (expr (((abs dark) * 20 - total * 10) + total - 1) \ total - 1))

The syntax expr is inspired by the eponymous UNIX tool expr. The expression at its right is expressed using almost standard formulae.

Writing arithmetic expressions is common when programming. Writing logic expressions and comparison expressions is also quite common. For this reason, the syntax expr comes with flavours allowing these expressions, too. Thus it is possible to write:

   (if (expr a < 0 and (k or b + c <> 9)))
      ...
instead of:
   (if (and (< a 0) (or k (not (= (+ b c) 9))))
      ...

SRFI 105, Curly-infix-expressions, already introduced the ability to write expressions in a more usual way. The current SRFI differs for the the following reasons:

However, SRFI-105 is compatible with this SRFI when $nfx$ and is defined as below:


   (define-syntax $nfx$
      (syntax-rules ()
         ((_ x ...) (expr x ...))))

Specification

This SRFI exports only one syntax item: expr. According to SRFI 261, this syntactic item can be imported using:

   (import (srfi srfi-266))

or on system supporting it, using:

   (import (srfi expr-266))

The syntactic item expr is followed by an expression whose elements E are separated by space (except if enclosed in braces):

   (expr E ...)

The expression E ... is made of variables, numbers and operators.

Operators are keywords, and can't be redefined. They are scanned as symbols, not as bindings to values. This rule is required for providing an unambiguous translation of a rich set of operators, and to provision it without requiring any import of any library.

Here is the list of operators defined for expr:

operator type priority operation
@ left 10 vector-ref
@. left 10 list-ref
@@ left 10 bytevector-u8-ref
@ prefix 10 unbox
** left 20 expt
- prefix 30 -
+ prefix 30 +
not prefix 30 not
? prefix 30 boolean --> 0 or 1
* list 40 *
/ list 40 /
\ left 40 quotient
% left 40 remainder
func 50 function call
+ list 50 +
- list 50 -
< comp 80 <
> comp 80 >
<= comp 80 <=
>= comp 80 >=
= comp 80 =
!= left 90 not =
and list 130 and
or list 140 or
implies left 150 implies
if else ternary 160 if
as in as 160 let-values
~ prefix 30 biwise-not
& list 100 bitwise-and
^ list 110 bitwise-xor
: list 120 bitwise-ior
~& left 100 bitwise-nand
~^ left 110 bitwise-eqv
~: left 120 bitwise-nor
fx- prefix 30 fxneg
fx~ prefix 30 fxnot
fx* left 40 fx*
fx\ left 40 fxquotient
fx% left 40 fxremainder
fx+ left 50 fx+
fx- left 50 fx-
fx<< left 60 fxarithmetic-shift-left
fx>> left 60 fxarithmetic-shift-right
fx< comp 80 fx<?
fx> comp 80 fx>?
fx<= comp 80 fx<=?
fx>= comp 80 fx>=?
fx= comp 80 fx=?
fx!= left 90 not fx=?
fx& list 100 fxand
fx^ list 110 fxxor
fx: list 120 fxior
fx- prefix 30 fl-
fl* left 40 fl*
fl/ left 40 fl/
fl\ left 40 flquotient
fl% left 40 flremainder
fl+ left 50 fl+
fl- left 50 fl-
fl< comp 80 fl<?
fl> comp 80 fl>?
fl<= comp 80 fl<=?
fl>= comp 80 fl>=?
fl= comp 80 fl=?
fl!= left 90 not fl=?

Types of operators are: prefix, left, list, comp, func, ternary.

prefix
OPERATOR X becomes (OPERATION X).
left
X OPERATOR Y becomes (OPERATION X Y).
list
X OPERATOR Y [OPERATOR Z]... becomes (OPERATION X Y Z...).
comp

X OPERATOR Y [OPERATOR Z]... becomes (OPERATION X Y Z...).

X COMP1 [Y COMP1]... Z COMP2 A [COMP2 B]... becomes (let ((tmp Z)) (and (COMP1 X Y... tmp) (COMP2 tmp A B...))).

func

X Y becomes (X Y).

X Y Z becomes (X (Y Z)) (right associativity).

ternary

X if Y else Z becomes (if Y X Z).

as

X as Y ... in Z becomes (let-values (((Y ...) X)) Z).

Expressions can also have sub-expression in parenthesis. In that case few cases are distinguished:

arguments

When argument of a call, spaces are interpreted as separation of arguments.

Then f (a b ...) expands as ((expr f) (expr a) (expr b) ...).

subexpression

When at the place of a term, the sub expression (a ...) expands as if replaced by (expr a ...).

escape

When a subexpression only contains one subexpression, it is replaced literaly by this subexpression. Then ((a ...)) becomes (a ...) without applying implicitely expr to the enclosed subexpression.

Application of the syntax expr should transform the expression to an equivalent scheme expression. It means that using expr has no runtime cost. It also means that expr is not required to optimize expressions. It is only required to translate the expression (for example, (expr + - 3) should become (+ (- 3)) even if it looks like being -3).

For example:

   (expr a + b + c < d <= x - y - z)

Should be translated to:

   (let ((tmp d)) (and (< (+ a b c) tmp) (<= tmp (- x y z))))

Implementation

Implementation of syntactic item expr can be made in many ways: using standard Scheme macros, using implementation specific macros, or, using internals of implementation.

The sample implementation given for guile 3 use syntax-case.

Source for the sample implementation.

Acknowledgements

Many thanks to writers of the UNIX tool expr.

© 2026 José Bollo.

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Editor: Arthur A. Gleckler