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> (let recur ((x x))
> (if (pair? x)
> (cons (car x) (recur (cdr x)))
> y))
But this borders on the absurd, because under this definition,
(append '(a b c . d) '(e f g)) => (a b c e f g)
that is, the d is silently dropped. What kind of sense does that make?
Plenty of sense -- the D isn't doing anything except terminating that
list. Once you get used to thinking of D as an empty list, Lars, you're going
to love it.
OK, I am getting a fairly consistent review here, so stay tuned for
a new compromise.
-Olin