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> (case (get-symbol) > ((true) #t) > ((false) #f) > (else => (lambda (x) x))) > >Without the => clause in case, we have to write: > >(let ((key (get-symbol))) > (cond ((eq? key 'true) #t) > ((eq? key 'false) #f) > (else key))) Am I missing something subtle? Per this example, we only have to write (let ((x (get-symbol))) (case x ((true) #t) ((false) #f) (else x))) The only difference between this and its => equivalent is the scope of 'x'.In cond, the => helps capture a useful value on the left-hand side of a cond clause that is otherwise not easily captured. It seems much less useful in a case, since the left-hand side of a case clause always consists of literal eqv-testable constants, and the capture trivial.
The main argument for this would seem to me to be symmetry with cond.