[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

Re: Cut and the operators mu and nu

This page is part of the web mail archives of SRFI 86 from before July 7th, 2015. The new archives for SRFI 86 contain all messages, not just those from before July 7th, 2015.

 * From: Jens Axel Søgaard <jensaxel@xxxxxxxxxxxx>
 | The specifications of mu and nu are:
   (mu <expr> ...)          => (lambda (f) (f <expr> ...))
   (nu <expr> ... <exprn>)  => (lambda (f) (apply f <expr> ... <exprn>))
   The <exprn> should be a list.

 | These are indeed useful operations. So useful that we already have
 | a srfi for them, namely srfi-26.
 | (cut <> <expr> ...) => (lambda (f) (f <expr> ...))
 | (cut apply <> <expr> ... <exprn>) => (lambda (f) (apply <expr> ... <exprn>))

It matters little whether we use (lambda (f) (f 1 2 3)) or (cut <> 1 2 3) or
(mu 1 2 3) or any other its equivalent.  The point is we know they can be used
in this way.

Nothing is complete unless you put it in final shape.