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Just a small question: Are the accessors visible in the protocol <exp>? Here is an example that would use this to copy a record. (define-record-type point (protocol (lambda (new) (case-lambda ((x y) (new x y)) ; Create new ((old-point) (new (point-x old-point) ; Copy existing (point-y old-point))))) (fields (immutable x) (immutable y))) Regards Andre