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Aubrey Jaffer wrote: > Since we treat integers as having two's-complement negations, the > two's-complement of an integer is its negation. The one's-complement > of an integer is computed by lognot: > > (define (lognot n) (- -1 n)) Isn't that backwards? Complement and negation are equivalent in ones- complement arithmetic; in twos-complement, the complement is equal to negation minus one. Perhaps I'm not understanding your explanation clearly. -- Bradd W. Szonye http://www.szonye.com/bradd