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Re: Param ordering; < and <=



>> Do you really think this makes a measurable difference in execution
>speed?
>
>In my example?  No.  As far as I know, both assembly versions will
>execute in the same number of cycles.  The difference between op< and
>op<=, while real, lies below the instruction level.
>


Where exactly? I can't find it... ;-)


cheers,
felix