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l, the ultimate curry that is not curry
Perhaps the basic problem here is just that "lambda" is cognitively a
single letter, but it requires six letters to spell in english. If
(define-syntax l (syntax-rules () ((l . foo) (lambda . foo))))
then you have a compact and powerful notation for "curry"-ing:
(curry + 2 <>) <=> (l (x) (+ 2 x))
(curry list 1 <> 2 <>) <=> (l (x y) (list 1 x 2 y))
If your system does unicode, then replace l with an actual lambda.
For the one-argument case, make l_ an abbreviation for l (_):
(define-syntax l_ (syntax-rules () ((l_ . foo) (l (_) . foo))))
then you have:
(curry + 2 <>) <=> (l_ (+ 2 _))
(curry < 1 <> 2) <=> (l_ (< 1 _ 2))
P.S. I can't decide whether or not these suggestions are supposed to
be taken seriously.