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Jussi Piitulainen <jpiitula@xxxxxxxxxxxxxxxx> writes: > If I do so: > > (define vec (vector "a" "b" "c")) > (define arr (share-array vec (shape 0 3) (lambda (j) (- 2 j)))) > > Then vec is a simple R5RS vector, but it is also the backing vector of > arr, and thus sharable and indeed shared, though it does not know it, > so to speak. > > Now if I do further: > > (define arr1 (share-array arr (shape 0 3) (lambda (j) (- 2 j)))) > > Then I get essentially the same array as vec. Its implementation might > be more expensive, though, while vec remains oblivious to all that is > going on. In fact SCM will define arr1 as the original vector vec in this case.